[tex]\sf \frac{225}{23} (488)-236b = 4428 \\ \\ \frac{109800}{23} + - 236b = 4428 \\ \\ -236b + \frac{109800}{23} = 4428 \\ \\ -236+ \frac{109800}{23} - \frac{109800}{23} = 4428 - \frac{109800}{23} \\ \\ -236b = \frac{-7956}{23} \\ \\ \boxed{{{\huge{{\bold{b = \dfrac{1989}{1357} }}}}}}[/tex]
