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The springs of a 1000 kg car compress 5.5 mm when its 68 kg driver gets into the driver's seat. If the car goes over a bump, what will be the frequency of vibrations?

Respuesta :

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1. Find the spring constant k:

F = mg = kx
68 * g = k * 0.0055m

k = 121287.273

2.Find the frequency f:
ω = 2πf = √k/m 

f = √(k / m)/ 2π =  1.7

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