Given △ABC, sin(A) =
A. cos(B)
B. sin(B)
C. cos(C)
D. tan (C)

we know that
In a right triangle ABC
m∠A+m∠C=[tex]90\°[/tex] -------> by complementary angles
so
[tex]sin(A)=cos (C)\\and\\cos(A)=sin (C)[/tex]
therefore
the answer is the option
C. cos(C)