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Combine these radicals
-6 √100+ √36

A. -66
B. -54
C. -6 √136
D. -6 √16

Please help!!

Respuesta :

-6√100+√36=-6(10)+6=-60+6=-54

Answer: B. -54

Answer:

option B is correct

-54

Step-by-step explanation:

Using radical and exponent laws:

[tex]\sqrt[n]{a^n} = a[/tex]

Given that:

[tex]-6\sqrt{100}+\sqrt{36}[/tex]

we can write 100 and 36 as:

[tex]100 = 10 \cdot 10= 10^2[/tex]

[tex]36 = 6^2[/tex]

then;

[tex]-6\sqrt{10^2}+\sqrt{6^2}[/tex]

Apply the rule;

[tex]-6\cdot 10+6[/tex]

[tex]-60+6[/tex]

Combines constant terms;

[tex]-54[/tex]

Therefore, Combine the given radicals we get, -54