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A pole is standing vertically in a lake in such a way that 1/5 of the pole is in the mud, 2/3 of the pole is in the water, 1/8 of the pole is above the water, and an additional piece of the pole is broken off. The broken piece is 1 foot 3 inches. what is the depth of the lake at the location of the pole?

Respuesta :

carlosego
The first thing we must calculate in this case is the total height of the post, which in this case will be given by:
 1/5 * 100 = 0.2 * 100 = 20%
 2/3 * 100 = 0.6667 * 100 = 66.67%
 1/8 * 100 = 0.125 * 100 = 12.5%
 The broken pierce is 1 foot 3 inches or equivalently 1.25 feets.
 This represents the remaining percentage:
 100-12.5-66.67-20 = 0.83%
 Then, using a rule of three we can get the height of the post
 1.25 ---> 0.83%
 x -------> 100%
 Clearing x we have_
 x = (100 / 0.83) * (1.25) = 150.60 feets.
 2/3 of the pole is in the water. Therefore, the depth of the lake is
 d = 150.60 * (2/3) = 100.4 feets
 answer
 the depth of the lake at the location of the pole is 100.4 feets

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