After collison they stick together and have same velocity Vf
From the momentum conservation,
(m1 + m2)Vf = m1v1 + m2v2
Second is moving with half of first cart speed, (m1 + m2)Vf = m1v + m2v / 2
2(m1 + m2)Vf = (2m1v + m2v) =>Vf = ((2m1 + m2) v) / 2(m1 + m2)
Identical carts so m1 = m2 = m
vf = 3mv / 4m => Vf = 3v / 4