Respuesta :
Hey there, Dudedan!
In a#b = a+2b, we have the first term, a, plus 2 times the second term, b.
Let's try that with 3#4.
3#4 = 3+2(4) =
3 + 8 = 11.
Hope this helps!
In a#b = a+2b, we have the first term, a, plus 2 times the second term, b.
Let's try that with 3#4.
3#4 = 3+2(4) =
3 + 8 = 11.
Hope this helps!
a # b = a + 2b
3 # 4 ⇒ a = 3 and b = 4
substitute:
3 # 4 = 3 + 2 · 4 = 3 + 8 = 11
3 # 4 ⇒ a = 3 and b = 4
substitute:
3 # 4 = 3 + 2 · 4 = 3 + 8 = 11