[tex](2x - 3)(x+4) = (2x)(x) + (2x)(4) - (3)(x) - (3)(4)\\\\=2x^2 + 8x - 3x - 12\\\\ = \boxed{\bf{2x^2+5x - 12}}[/tex]
We used the FOIL method, which is basically:
[tex](a+b)(c+d) = ac + ad + bc + bd[/tex]
Just becareful about the signs in the parenthesis. :)
