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Mike shoots a large marble (Marble A, mass: 0.05 kg) at a smaller marble (Marble B, mass: 0.03 kg) that is sitting still. Marble A was initially moving at a velocity of 0.6 m/s, but after the collision it has a velocity of –0.2 m/s. What is the resulting velocity of marble B after the collision? Be sure to show your work for solving this problem along with the final answer

Respuesta :

monettekevinozjram
v= m/d
V = .8kg/.8m/s
v= 1
initial momentum = final momentum
assume a linear collision, since no angles are given
0.05kg*0.6m/s + 0 = 0.05kg*-0.2m/s + 0.03kg*v
v = 1.3 m/s

It should be noted that this data isn't valid -- the larger mass marble will continue to have "positive" velocity after colliding with a smaller mass marble. Think Newton's cradle. I suspect that the overall KE has increased in this problem, a no-no (but I haven't calculated it).

I hope that helped

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