Respuesta :

I believe the answer is 21 classes.
Here are the equations:
63 + 12n =
and
15n =

So we need to figure out when they will meet up at the same value...

63 + 12( )=
and
15 x ( )=

So for this, the starting fee is $63 ahead of the one without the starting fee.

So we find the multiple where each equals the same value...

63 + 12(21)= 315
and
15(21)= 315


12 x 21 = 252
252 + 63 = 315

15 x 21 = 315


So after 21 classes, the cost will be the same.




Hope this helped! :)