Answer:
Answer:K = 5.04 × 10⁵²
Explanation:
The relation between equilibrium constant and emf is:
[tex]E^{0}_{cell} = \frac{0.0592}{n} (logK)[/tex]
Given
[tex]E^{0}_{cell} = 1.56[/tex]
n = 2 (for the given reaction)
Putting values
[tex]1.56=\frac{0.0592}{2}(logK)[/tex]
logK=52.70
K = 5.04 × 10⁵²
