Answer: The product is [tex]9a^8+24a^4+16[/tex]
Step-by-step explanation:
Since we have given that
[tex](3a^4+4)^2[/tex]
As we know that
[tex](a+b)^2=a^2+2ab+b^2[/tex]
So, it becomes,
[tex](3a^4 + 4)^2=(3a^4)^2+2\times 3a^4\times 4+(4)^2\\\\=9a^8+24a^4+16[/tex]
Hence, the product is [tex]9a^8+24a^4+16[/tex]
