Respuesta :

[tex]2x+2a=20 \ \textgreater \ \mathrm{Subtract\:}2a\mathrm{\:from\:both\:sides} \ \textgreater \ 2x+2a-2a=20-2a[/tex]

[tex]\mathrm{Simplify} \ \textgreater \ 2x=20-2a \ \textgreater \ \mathrm{Divide\:both\:sides\:by\:}2 \ \textgreater \ \frac{2x}{2}=\frac{20}{2}-\frac{2a}{2}[/tex]

[tex]\frac{2x}{2} \ \textgreater \ \mathrm{Divide\:the\:numbers:}\:\frac{2}{2}=1 \ \textgreater \ x[/tex]

[tex]\frac{20}{2}-\frac{2a}{2} \ \textgreater \ \mathrm{Apply\:rule}\:\frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c} \ \textgreater \ \frac{20-2a}{2} [/tex]

[tex]20-2a \ \textgreater \ \mathrm{Rewrite\:as} \ \textgreater \ 2\cdot \:10-2a \ \textgreater \ \mathrm{Factor\:out\:common\:term\:}2 [/tex]

[tex]2\left(-a+10\right) \ \textgreater \ \frac{2\left(-a+10\right)}{2} \ \textgreater \ \mathrm{Divide\:the\:numbers:}\:\frac{2}{2}=1 \ \textgreater \ x = -a+10[/tex]

Hope this helps!