Answer: The equivalence factor set that should be used is [tex]\frac{126g}{12.01g}\times 6.022\times 10^{23}[/tex]
Explanation:
Molar mass of a substance is defined as the mass of one mole of a substance.
We know that:
Molar mass of carbon atom = 12.01 g/mol
Given mass of carbon atom = 126 grams
Applying unitary method:
12.01 grams of carbon occupies 1 mole
So, 126 grams of carbon will occupy = [tex]\frac{1mol}{12.01g}\times 126g[/tex]
According to mole concept:
1 mole of an element contains [tex]6.022\times 10^{23}[/tex] number of atoms
So, [tex]\frac{1mol}{12.01g}\times 126g[/tex] of carbon will contain = [tex]\frac{1mol}{12.01g}\times 126g\times \frac{6.022\times 10^{23}}{1mol}=\frac{126g}{12.01g}\times 6.022\times 10^{23}[/tex] number of atoms
Hence, the equivalence factor set that should be used is [tex]\frac{126g}{12.01g}\times 6.022\times 10^{23}[/tex]
