Ye has his own business. He checks his sales receipts three times a day. One day, his afternoon sales eere $50 more than his morning sales, and his evening sales were three times his afternoon sales. If his total slaes for the day were $1,000, what were his evening sales?

Let his morning sakes be $m, then afternoon sales were m+50, and his evening sales were 3m+150.
Total sales=m+m+50+3m+150=1000.
5m=1000-200=800, so m=800/5=$160. His evening sales were 3(160+50)=3×210=$630.

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windyyork windyyork · Answer 2 · 2019-08-14T07:19:15+02:00

Answer: Hence, his evening sales were $630.

Step-by-step explanation:

Let the sales in the morning be 'x'

Let the sales in afternoon be x+50

Let the sales in the evening be 3(x+50).

Total sales for the day = $1000

According to question, it becomes

[tex]x+x+50+3(x+50)=1000\\\\2x+50+3x+150=1000\\\\5x+200=1000\\\\5x=1000-200=800\\\\x=\dfrac{800}{5}\\\\x=160[/tex]

So, his evening sales would be

[tex]3(x+50)\\\\=3(160+50)\\\\=3\times 210\\\\=630[/tex]

Hence, his evening sales were $630.