Respuesta :
Answer:
The required equation of line is y=-6x-57.
Step-by-step explanation:
The point slope form of a line is
[tex]y-y_1=m(x-x_1)[/tex]
Where m is slope of the line.
It is given that a line that passes through (–9, –3) and has a slope of –6.
Substitute m=-6, x₁=-9 and y₁=-3 in the above equation.
[tex]y-(-3)=-6(x-(-9))[/tex]
[tex]y+3=-6x-54[/tex]
Subtract 3 from both the sides.
[tex]y=-6x-54-3[/tex]
[tex]y=-6x-57[/tex]
Therefore the required equation of line is y=-6x-57.
