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If trapezoid ABCD was reflected over the y-axis, reflected over the x-axis, and rotated 180°, where would point A' lie?
[Hint: Place your coordinates in the blank with no parentheses and a space after the comma in the form: x, y]

If trapezoid ABCD was reflected over the yaxis reflected over the xaxis and rotated 180 where would point A lieHint Place your coordinates in the blank with no class=

Respuesta :

the answer is 1, 1 because it returns back to its first position

Answer: coordinates x = 1, y = 1.


Explanation:


You can deduce the answer analytically by using these mathematical rules:


1. First transformation. Reflection over the y-axis means that the image will keep the same y-coordinate and negate the x-coordinate (the image will end in the left quadrant at the same height):

  • rule (x,y) → (- x, y)

          A(1,1) → A'(-1,1)

          B(2,2) → B'(-2,2)

          C(4,2) → C'(-4,2)

          D(5,1) → D'(-5,1)


2. Second transformation. The reflection over the x-axis tansforms the image by keeping the same x-coordinate and negating the y-coordinate, the image will end in the fhird quadrant right below the previous image:

  • rule (x,y) → (x, - y)

          A'(-1,1) → A''(-1,-1)

          B'(-2,2) → B''(-2,-2)

          C'(-4,2) → C''(-4,-2)

          D'(-5,1) → D''(-5,-1)


3. Third transformation. The rotation 180° (either counterclockwise or clockwise) negates both coordinates x and y:

  • rule (x,y) → (- x, - y)

          A''(-1,-1) → A'''(1,1) ← this is the answer

          B''(-2,-2) → B'''(2,2)

          C''(-4,-2) → C'''(4,2)

          D''(-5,-1) → D'''(5,1)

As you see the final images of every point correspond to same original point.