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An electron in the n=7 level of the hydrogen atom relaxes to a lower energy level, emitting light of 1005 nm. part a what is the value of n for the level to which the electron relaxed? express your answer as an integer.

Respuesta :

prinskumarpatel
your answer is m = 2 

Answer:

final relaxed state is m = 3

Explanation:

As we know that due to transition of electron the wavelength emitted is given as

[tex]\frac{1}{\lambda} = Rz^2(\frac{1}{m^2} - \frac{1}{n^2})[/tex]

now we know that

[tex]\lambda = 1005 nm[/tex]

now we have

[tex]\frac{1}{1005\times 10^{-9}} = 1.01\times 10^7(\frac{1}{m^2} - \frac{1}{49})[/tex]

now by solving above equation for m we will have

m = 3

so the final relaxed state is m = 3

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