This problem only needs the conversion factor for grams to lbs and centimetre to inches. The conversion factor that would be used are 1 lb = 453.592 grams and 1 inch = 2.54 cm. Thus you would divide 3.34 grams with 453.592 grams then multiply it with the cube of 2.54 cm. The answer would be 0.1207 lb/in^3.
As per the question the average density of the moon [ω][tex]= 3.34gram/cm^3[/tex]
The density of a substance is defined as mass per unit volume.Mathematically density ω =[tex]\frac{mass}{volume}[/tex]
We are asked to convert this value from [tex]gram/cm^3[/tex] to [tex]pound/inch^3[/tex]
We know that one gram is equal to .0022 pound i.e
1 gram=.0022 lb
Again one centimetre is equal to .394 inch i.e
1 cm=.394 inch
Hence density[ ω]= 3.34 [tex]gram/cm^3[/tex]
⇒ω[tex]= 3.34*\frac{0.0022lb}{[0.399inch]^{3} }[/tex]
⇒ω[tex]=3.34*\frac{.0022}{.061162984} lb/inch^3[/tex]
⇒ω[tex]=0.120138 lb/inch^3[/tex] [ans]
