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The perimeter, P, of a rectangle is the sum of twice the length and twice the width.
P = 2(l+w) units
P = 2(5)+2(9) units
P = 4x units
P = (l+l)+(w+w) units
P = 2(x+3) units

Respuesta :

chewhiuyonowuwox
The answer is P = 2(l+w) units.

This is because when you let the perimeter of the rectangle be P, the length of the rectangle be l and the width of the rectangle be w.

The information above can be expressed as the following equation,
P = 2l + 2w

You can then factorise out the common factor, 2.
P = 2(l+w)

Thus, the answer is P = 2(l+w) units.

Answer:

P=2(l+w)

Step-by-step explanation:

It is given that perimeter, P, of a rectangle is the sum of twice the length and twice the width.

Let length of rectangle is l and width of the rectangle is w.

Perimeter = 2 × Length + 2 × Width

[tex]P=2\times l+2\times w[/tex]

[tex]P=2l+2w[/tex]

Taking out common factors.

[tex]P=2(l+w)[/tex]

[Note: (l+l)+(w+w) units is also true but according to the statement only option 1 is true]

Therefore, the correct option is 1.

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