Answer:
Distance moved = 9.0 m
Displacement magnitude = 4.6 m
Direction : Northwards
Explanation:
the quarter back pedals 2.2 m South
Then he pedal 6.8 m North
So here we can say that total distance moved by the quarterback is
[tex]Distance = 6.8 + 2.2 = 9.0 m[/tex]
Now to find the displacement we need to add them with direction
so we have
[tex]\vec d = 6.8 - 2.2 = 4.6 m[/tex]
Direction : Towards North
The total distance covered by the cyclist is 9 m, while the displacement is 4.6 m northwards.
The given parameters;
Distance is scalar quantity. That is, distance can be represented in a complete sense with magnitude only.
The total distance covered during the motion = 2.2 m + 6.8 m = 9m
The direction describes the position of the total displacement.
The displacement = (6.8 m - 2.2 m) northward
The displacement = 4.6 m northward.
Thus, we can conclude that the total distance covered by the cyclist is 9 m, while the displacement is 4.6 m northwards.
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