Suppose that two cards are dealt from a standard 52-card poker deck. let a be the event that the sum of the two cards is 8 (assume that aces have a numerical value of 1). how many outcomes are in a?
Case 1: You have an Ace and a seven. There are 4 ways to pick 1 Ace out of 4. There are 4 ways to pick 1 seven out of 4. -----> 4*4 = 16 There are 16 ways to be dealt an Ace and a seven.
Case 2: You have a two and a six. In the same way there are 4*4=16 ways to be dealt a two and a six.
Case 3: You have a three and a five. In the same way there are 4*4=16 ways to be dealt a three and a five.
Case 4: You have 2 fours. There are 6 ways to get 2 fours out of 4. (4 choose 2)
