From the given values we can
generate the equations:
x = vx*t
y = 0.95 - 1/2*g*t^2
where x refers to displacement in horizontal direction, y refers
to displacement in vertical direction, and t is time, while vx is velocity of
the cart in the x direction, and g is the acceleration due to gravity = 9.8 m/s^2
At it's landing point we have x = 0.4, y = 0:
0.4 = vx*t
0 = 0.95 - 1/2*9.8*t^2
Therefore combining the equations and
solving:
t = 0.44 s s
vx = 0.91 m/s
