Respuesta :

[tex]x = 1 \pm \sqrt{5} \\ \\ x - 1 = \pm \sqrt{5} \\ \\ (x-1)^2 = (\sqrt{5})^2 = 5 \\ \\ x^2 -2x +1 = 5 \\ \\ x^2 -2x -4 = 0[/tex]
202207

Answer:

its d

Step-by-step explanation: