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A spinner is divided into three equal parts A, B, and C. The repeated experiment of spinning the spinner twice is simulated 125 times. A table of outcomes is shown.


Outcome Frequency
A, A 15
A, B 12
A, C 10
B, A 18
B, B 15
B, C 17
C, A 11
C, B 13
C, C 14

Based on the table, for what probability can you expect the spinner to not land on B?
0.10
0.33
0.40
0.66

Respuesta :

Answer:

0.40

Step-by-step explanation:

To find the probability of the spinner not landing on B, we need to sum the frequencies of outcomes where B does not appear and divide it by the total number of experiments.

From the given outcomes, the combinations where B does not appear are:

1. A, A

2. A, C

3. C, A

4. C, C

So, the total frequency of outcomes where B does not appear is:

[15 (A, A) + 10 (A, C) + 11 (C, A) + 14 (C, C) = 50]

Now, let's calculate the probability of not landing on B:

50/125 = 0.40

So, the probability of the spinner not landing on B is \(0.40\). Therefore, the correct answer is option **0.40**.

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