paudyalsayam paudyalsayam

27-03-2024
Mathematics

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respectively. In the given figure ABCDEF is the regular hexagon then show that: AB+ AC + AD + EA+FA = 4AB.

respectively In the given figure ABCDEF is the regular hexagon then show that AB AC AD EAFA 4AB class=

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lo286907 lo286907

27-03-2024

Answer: Here's some proof.

Step-by-step explanation:

AB=BC=CD=DE=EF=FA

so express it in AB+AC+AD+EA+FA in terms of AB.

AB+AC+AD+EA+FA = AB+AB+AB+AB+AB = 5AB

So AB+AC+AD+EA+FA = 5AB

So now express in 4AB:

comparing 4AB and AB+AC+AD+EA+FA, we see that 4AB=5AB

therefore, AB+AC+AD+EA+FA=4AB

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