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The first aircraft has 75 more seats than the second aircraft. The third aircraft has 49 fewer seats than the second aircraft. If their total number of seats is 401​, find the number of seats for each aircraft.

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musiclover10045

1st = 75+x

2nd = x

3rd = x-49


401 = 75 +x+ x+ +x-49

401 = 75+3x-49

401 = 3x+26

375=3x

x=375/3 = 125


1st = 125+75 = 200

2nd = 125

3rd = 125-49 = 76

200 + 125 +76 = 401

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