Ruby8385 Ruby8385 30-08-2017 Mathematics contestada Factor completely 16a^3b^7 + 2a^6 b4 − 22a ^4 b^5. 2(8a3b7 + a6b4 − 11a4b5) 2a3b4(8b3 + a3 − 11ab) a3b4(16b3 + 2a3 − 22ab) 8b3 + a3 − 11ab