Answer: We can conclude that, [tex]\triangle OAB\cong \triangle PD E[/tex].
Explanation: Since, If two circles are congruent then their radius is equal.
Therefore, we can say, OA=OB=PD=PE.
Since, in triangles OAB and PDE,
OA=PD,
OB=PE,
And, AB=DE ( given)
Therefore, by SSS postulate we can say, [tex]\triangle OAB\cong \triangle PD E[/tex] .
Note: we can also say by the diagram, [tex]\angle AOB[/tex] and [tex]\angle PD E[/tex] are congruent.
