Respuesta :

forgive me if I've read your question wrong but I see
[tex] \frac{20-45x^2}{6x^2-x-2} [/tex]
[tex] = \frac{5(4-9x^2)}{6x^2-x-2} = \frac{5(2-3x)(2+3x)}{6x^2-x-2} [/tex]
[tex]= \frac{5(2-3x)(2+3x)}{(3x+2)(3x-1)} = \frac{5(2-3x)}{3x-1} [/tex]

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