Respuesta :

[tex]|6x-3|+4\ \textless \ 19 \\ \ \textless \ =\ \textgreater \ |6x-3| \ \textless \ 19 - 4 \\ \ \textless \ =\ \textgreater \ |6x-3| \ \textless \ 15 \\ \ \textless \ =\ \textgreater \ -15 \ \textless \ 6x - 3 \ \textless \ 15 \\ \ \textless \ =\ \textgreater \ - 12 \ \textless \ 6x \ \textless \ 18 \\ \ \textless \ =\ \textgreater \ -2 \ \textless \ x \ \textless \ 3 \\ [/tex]

x belon to the interval [-2;3]