Respuesta :

[tex]\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}\quad \begin{cases} r=radius\\ h=height\\ ------\\ r=\frac{h}{5}\implies 5r=h \end{cases}\implies V=\cfrac{\pi r^25r}{3} \implies V=\cfrac{5\pi r^3}{3}[/tex]

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