Respuesta :
horizontal shift 2 uniits to the right gives
y = 5 sqrt(x - 2) + 3
Then a vertical stretch factor 3 gives
y = 3[5sqrt(x-2) + 3)
or y = 15sqrt(x - 2) + 9
y = 5 sqrt(x - 2) + 3
Then a vertical stretch factor 3 gives
y = 3[5sqrt(x-2) + 3)
or y = 15sqrt(x - 2) + 9
Answer:Explained
Step-by-step explanation:
Given
equation of line is [tex]y=5\sqrt{x}+3 [/tex]
First We need to shift 2 units horizontally
Thus [tex]y=5\sqrt{x-3}+3[/tex]
Now Stretched by a factor of 3 about the fixed y=3
that is the y is 3 times of previous value
[tex]y=3\left ( 5\sqrt{x-3}+3\right )[/tex]
