For this problem, we use the equations derived from the projectile motion. Particularly, we use the trajectory of the projectile equation written below:
y = xtanθ + gx/2v₀²cosθ
where
y is the vertical height
x is the horizontal distance
θ is the launch angle
g is 9.81 m/s²
v₀ is the initial velocity
Since it was thrown horizontally, θ = 0°. Substituting the values,
y = 17tan0° + (9.81)(17)/2(9.50)²cos0°
y = 0.924 m
