hubbsy23seb hubbsy23seb

27-08-2017
Mathematics

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evaluate the limit lim h → 0 (−5 + h)2 − 25/h

Respuesta :

SummerizMyName14 SummerizMyName14

27-08-2017

((5+h)^2 - 25)/h
= (25 + 10h + h^2 - 25)/h
= [h(h + 10)]/h
= h + 10 => take the limit
= 10

Hope this helps

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