The solutions to the equation are [tex] \frac{2 +/- \sqrt{15)}}{11} [/tex].
You can find the answer to any quadratic by using the quadratic formula. The formula is below.
[tex] \frac{-b +/- \sqrt{b^{2}-4ac}}{2a} [/tex]
Then find a (the number attached to x^2), b (the number attached to x) and c (the constant). This will allow you to plug in and solve.
[tex] \frac{4 +/- \sqrt{-4^{2}-4(11)(-1)}}{2(11)} [/tex]
[tex] \frac{4 +/- \sqrt{16 + 44}}{22} [/tex]
[tex] \frac{4 +/- \sqrt{60)}}{22} [/tex]
[tex] \frac{2 +/- \sqrt{15)}}{11} [/tex]
Answer: it’s A
Step-by-step explanation:
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