Respuesta :
NH₄Cl(s) → NH₄⁺(aq) + Cl⁻(aq)
(1) NaOH + NH₄Cl → NaCl + NH₃ + H₂O
Na⁺ + OH⁻ + NH₄⁺ + Cl⁻ → Na⁺ + Cl⁻ + NH₃ + H₂O
(2) OH⁻(aq) + NH₄⁺(aq) → NH₃(g) + H₂O(l)
(1) NaOH + NH₄Cl → NaCl + NH₃ + H₂O
Na⁺ + OH⁻ + NH₄⁺ + Cl⁻ → Na⁺ + Cl⁻ + NH₃ + H₂O
(2) OH⁻(aq) + NH₄⁺(aq) → NH₃(g) + H₂O(l)
In this case, the NH4Cl is specified as a solid.
Its important to note that, as Im not convinced it can be written other than
Na+ (aq) + OH-(aq) NH4Cl(s) ----> NaCl(s) + NH3(g) + H2O(l)
which would serve as your ionic/net equation.
your molecular would be
NaOH(aq) + NH4Cl(s) ---> NaCl(s) + NH3(g) + H2O(l)
am curious what the higher ups have to say regarding this one! ;-)