A rectangle is placed around a semicircle as shown below. the width of the rectangle is 6ft . find the area of the shaded region. use the value 3.14 for π , and do not round your answer. be sure to include the correct unit in your answer.

Respuesta :

As the figure is missing, I will do the most logical assumptions and explain the way to solve the problem.

Assumptions:

1) radius of the semicircle = width of the rectangle = 6ft

2) length of the rectangle = 2*radius of the semicircle = 12 ft

3) Area of the shaded region = area of the rectangle - area of the semicircle

Solution

area of the rectangle = width * length = 6 ft * 12 ft = 72 ft^2

area of the semicircle = [1/2]*π*(r^2) = [1/2]*3.14*(6ft)^2 = 56.52 ft^2

area of the shaded region = 72 ft^2 - 56.52 ft^2 = 15.48ft^2

Answer: 15.48 ft^2

The shaded region is by assumption the region which is not covered by the semicircle in in given rectangles.

The area of the shaded region is given by 15.48 sq. ft.

What is a semicircle?


A semicircle is a circle cut in half. Thus, one circle produces two semicircle.

How to find the area of the shaded region?

Firstly we will find the area of the rectangle and then subtract the area of the semicircle to find the are of the shaded region.

Since the radius of the semicircle is equal to width of the rectangle(6 ft), thus the length of the diameter of the circle( twice the radius which is 12 ft) serves as length of the considered rectangle.

Thus, we have:

[tex]\text{Area of the given rectangle\:} = 6 \times 12 = 72 \: \rm ft^2[/tex]


Since the semicircle is having radius of 6 ft, thus:

[tex]\text{Area of semicircle} = \dfrac{\pi r^2}{2} = \dfrac{3.14 \times 6^2}{2} = 56.52 \: \rm ft^2[/tex]

Thus, area of the shaded region will be equal to area of rectangle - area of semicircle = 72 - 56.52 = 15.48 sq. ft.

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