Respuesta :
f(x)=-x^2+60x-116
f(x)+116=-x^2+60x
-f(x)-116=x^2-60x
-f(x)-116+900=x^2-60x+900
-f(x)+784=(x-30)^2
f(x)-784=-(x-30)^2
f(x)=-(x-30)^2+784
So the vertex is the point (30, 784)
Or you could commit to memory that the vertex for a parabola is always:
( -b/(2a), (4ac-b^2)/(4a) )
f(x)+116=-x^2+60x
-f(x)-116=x^2-60x
-f(x)-116+900=x^2-60x+900
-f(x)+784=(x-30)^2
f(x)-784=-(x-30)^2
f(x)=-(x-30)^2+784
So the vertex is the point (30, 784)
Or you could commit to memory that the vertex for a parabola is always:
( -b/(2a), (4ac-b^2)/(4a) )