Respuesta :
[tex]a_1=52\\
d=2\\
n=93\\\\
a_n=a_1+(n-1)\cdot d\\\\
a_{93}=52+(93-1)\cdot2=52+2(93-1)
[/tex]
They want to construct this in the form of an arithmetic sequence which as the form:
a(n)=a+d(n-1), where a=initial value, d=common difference.
In this case a=52 and d=2, so our formula is:
a(n)=52+2(n-1) and if we are looking for the 93 term we have
a(93)=52+2(93-1)
a(n)=a+d(n-1), where a=initial value, d=common difference.
In this case a=52 and d=2, so our formula is:
a(n)=52+2(n-1) and if we are looking for the 93 term we have
a(93)=52+2(93-1)