Respuesta :
10≤n<100
So the number of two digit numbers is 99-10+1=90
The only combinations that sum to 5 are 14, 23, 32, 41, 50 so
P(sum=5)=5/90
P(sum=5)=1/18
So the number of two digit numbers is 99-10+1=90
The only combinations that sum to 5 are 14, 23, 32, 41, 50 so
P(sum=5)=5/90
P(sum=5)=1/18
There are 90 two digit numbers.
The numbers that have 5 as the sum of their digits are:
14,23,32,41,50
which are 5 numbers out of the possible 90
Therefore the probabilty is 5/90 or 1/18
The numbers that have 5 as the sum of their digits are:
14,23,32,41,50
which are 5 numbers out of the possible 90
Therefore the probabilty is 5/90 or 1/18