We are given the equation:
13x^2 + 6√3 xy + 7y^2 - 16 = 0
Based on the general equation of conic sections:
Ax^2 + Bxy + Cy^2 + Dx + Ey + F = 0,
A = 13
B = 6√3
C = 7
D = 0
E = 0
F = -16
So we can find the graph of the equation by solving for the discriminate B^2 - 4AC
B^2 - 4AC, substitute given:
(6^2 * 3) - 4 (13 * 7) = -256
since the discriminate is less than zero, the graph could be a circle or a parabola. In this case, the values of A and C are not equal, then our graph is a parabola.
