an input force of 20 newtons is applied to a lever at a distance of 2 meters from the fulcrum and object 0.5 M away from the fulcrum and on the other side is lifted by the 20-N force what is the output force?
The input force of 20 N should use the effect of the lever to lift the weight W on the other side of the fulcrum. Therefore the output force is equal to the weight lifted.
Moment balance about the fulcrum yields W*0.5 - Fin*2 = 0 [tex](W \, N)*(0.5 \, m) - (20} \, N)*(2 \, m) = 0\\
W= \frac{40}{0.5}=80 \, N [/tex]
Because the output force is equal to W, [tex]F_{out} = 80 \, N[/tex]
