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Explain your thinking process of all interferes between Square root of 12 and square root of 40

Explain your thinking process of all interferes between Square root of 12 and square root of 40 class=

Respuesta :

So since 3^2 = 9 < 12, 4^16 > 12, then 4 will be the first number of the sum

Since 6^2 = 36 < 40, 7^2 = 49 > 40, then 6 will be the last number of the sum

Therefore, the sum of integers is: 4+5+6 = 15