1) Balanced chemical equation
4NH3(g) + 5O2(g) ---> 4NO(g) + 6H2O(g)
2) State the molar ratios
4 mol NH3 : 5 mol O2 : 4 mol NO : 6 mol H2O
3) Convert 88.9 g of ammonia to moles, using the molar mass
molar mass of NH3 = 14 g/mol + 3 * 1 g/mol = 17 g/mol
number of moles = mass in grams / molar mass = 88.9 g / 17 g/mol = 5.23 mol NH3
4) Make the proportion
4 mol NO / 4 mol NH3 = x / 5.23 mol NH3=> x = 5.23 mol NO
5) Convert 5.23 mol NO to grams
molar mass NO = 14 g/mol + 16g/mol = 30 g/mol
mass = number of moles * molar mass = 5.23 mol * 30 g/mol = 156.9 g ≈ 157 g
Answer: 157 grams
