Respuesta :
H₂SO₄(aq) + 2NaOH(aq) → Na₂SO₄(aq) + 2H₂O(l)
2H⁺ + SO₄²⁻ + 2Na⁺ + 2OH⁻ → 2Na⁺ + SO₄²⁻ + 2H₂O
H⁺ + OH⁻ → H₂O (the net ionic equation)
2H⁺ + SO₄²⁻ + 2Na⁺ + 2OH⁻ → 2Na⁺ + SO₄²⁻ + 2H₂O
H⁺ + OH⁻ → H₂O (the net ionic equation)
The net ionic equation for the reaction will be [tex]\rm \bold{2\;H^+\;+\;2\;OH^-\;\rightarrow\;2\;H_2O}[/tex].
A chemical equation has been the chemical representation of the reactants involved with the formed products. The ionic equation has been consisted of the ionic form of the reactants and products.
The reaction for Sulfuric acid and Sodium hydroxide will be:
[tex]\rm H_2SO_4\;+\;2\;NaOH\;\rightarrow\;Na_2SO_4\;+\;2\;H_2O[/tex]
The ionic equation for reactants will be:
[tex]\rm H_2SO_4\;+\;2\;NaOH[/tex] = [tex]\rm 2\;H^+\;+\;SO_4^2^-\;+\;2\;Na^+\;2\;OH^-[/tex]
The ionic equation for the products has been:
[tex]\rm Na_2SO_4\;+\;2\;H_2O[/tex] = [tex]\rm 2\;Na^+\;+\;SO_4^2^-\;+\;4\;H^+\;+\;2\;O^-[/tex]
The total equation will be:
[tex]\rm 2\;H^+\;+\;SO_4^2^-\;+\;2\;Na^+\;2\;OH^-[/tex] [tex]\rightarrow[/tex] [tex]\rm 2\;Na^+\;+\;SO_4^2^-\;+\;4\;H^+\;+\;2\;O^-[/tex]
In the net ionic equation, the ions same on both sides of the products and reactants are eliminated.
The net ionic equation for the reaction will be:
[tex]\rm 2\;H^+\;+\;2\;OH^-\;\rightarrow\;4\;H^+\;+\;2O^-[/tex]
[tex]\rm \bold{2\;H^+\;+\;2\;OH^-\;\rightarrow\;2\;H_2O}[/tex]
For more information about the ionic equation, refer to the link:
https://brainly.com/question/21883718
