Find the length of AH for which MATH is a parallelogram.
A. 3B. 4C. 6D. 10

Answer:
Step-by-step explanation:
Alright, lets get started.
For being this quadrilateral to be a parallelogram, the diogonals must be bisected.
It means,
[tex]AP=HP[/tex]
[tex]2f-5=5f-17[/tex]
taking similar terms together,
[tex]5f-2f=17-5[/tex]
[tex]3f=12[/tex]
[tex]f=4[/tex]
So,
[tex]AP=2f-5=2*4-5=3[/tex]
Similarly,
[tex]HP=5f-17=5*4-17=3[/tex]
[tex]AH=AP+HP[/tex]
[tex]AH=3+3=6[/tex]
AH = 6 : Answer
Hope it will help :)