Respuesta :

[tex]\bf \qquad \textit{Continuously Compounding Interest Amount}\\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\to& \$12,000\\ r=rate\to 11\%\to \frac{11}{100}\to &0.11\\ t=years\to &13 \end{cases} \\\\\\ A=12000e^{0.11\cdot 13}[/tex]