Answer:
x=0 is the zero of the given function
Step-by-step explanation:
[tex]f(x) = \frac{4x^2-36x}{x-9}[/tex]
To find zeros of the function we replace f(x) with 0
then we solve for x
[tex]0= \frac{4x^2-36x}{x-9}[/tex]
Now we factor the numerator 4x^2 -36x
[tex]0= \frac{4x(x-9)}{x-9}[/tex]
Cancel out x-9 at the top and bottom
0=4x (divide by 4 on both sides)
x=0
So x=0 is the zero of the given function
