Let the legs of the right triangle be a and b and the hypothenus be c, then by the pythagoras theorem
[tex]a^2+b^2=c^2[/tex]
Given that
[tex]a =x^2-y^2[/tex]
Let a = 11, then
[tex]x^2-y^2=11[/tex]
By trial and error, we can find that the value of x = 6 and the value of y = 5.
i.e.
[tex]x^2-y^2=6^2-5^2=36-25=11[/tex]
Thus,
b = 2(6)(5) = 60
and
[tex]x^2+y^2=6^2+5^2=36+25=61[/tex]
Therefore, the other leg = 60 and the hypotenuse = 61.